I need to output a jpeg image in this page. Looking at the code below, i have a form set up which displays data to the user. Within this form or underneath the form i need to output an image. The code is run as a PHP file so the normal HTML tag would not work. Any ideas?\[code\]<!DOCTYPE html> <?php session_start(); ?> <html> <head> <meta charset="utf-8" /> <meta name="viewport" content="width=device-width, initial-scale=1" /> <meta name="apple-mobile-web-app-capable" content="yes" /> <meta name="apple-mobile-web-app-status-bar-style" content="black" /> <title> </title> <link rel="stylesheet" href="https://ajax.aspnetcdn.com/ajax/jquery.mobile/1.2.0/jquery.mobile-1.2.0.min.css" /> <link rel="stylesheet" href="http://stackoverflow.com/questions/15904168/my.css" /> <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js"> </script> <script src="https://ajax.aspnetcdn.com/ajax/jquery.mobile/1.2.0/jquery.mobile-1.2.0.min.js"> </script> <script src="http://stackoverflow.com/questions/15904168/my.js"> </script> <!-- User-generated css --> <style> </style> <!-- User-generated js --> <script> try { $(function() { }); } catch (error) { console.error("Your javascript has an error: " + error); } </script> </head> <body> <!-- Home --> <div data-role="page" id="page1"> <div data-theme="a" data-role="header"> <a data-role="button" data-theme="d" href="http://stackoverflow.com/questions/15904168/login.html" data-icon="arrow-l" data-iconpos="left" class="ui-btn-left"> Back </a> <a data-role="button" href="http://stackoverflow.com/questions/15904168/index.html" data-icon="home" data-iconpos="right" data-theme="d"class="ui-btn-right"> Home </a> <h3> Book Car </h3> </div> <div data-role="content"> <h3> Select the car to rent from the availability: </h3> <br /> <?php { mysql_connect("localhost" , "" , "") or die (mysql_error()); mysql_select_db("") or die(mysql_error()); $pid=intval($_SESSION["User_id"]); $query = "SELECT `car`, `details`, `price` FROM `Car`"; //executes query on the database $result = mysql_query ($query) or die ("didn't query"); //this selects the results as rows $num = mysql_num_rows ($result); while($row=mysql_fetch_assoc($result)) { $_SESSION['car'] = $row['car']; $_SESSION['details'] = $row['details']; $_SESSION['price'] = $row['price']; } } ?> <!DOCTYPE html> <html> <body> <form action="demo_form.asp"> Car: <input type="text" name="country" value="http://stackoverflow.com/questions/15904168/<?php echo $_SESSION['car']; ?>" readonly><br> Details: <input type="text" name="country" value="http://stackoverflow.com/questions/15904168/<?php echo $_SESSION['details']; ?>" readonly><br> Price: <input type="text" name="country" value="http://stackoverflow.com/questions/15904168/<?php echo $_SESSION['price']; ?>" readonly><br> <input type="submit" value="http://stackoverflow.com/questions/15904168/Submit"> </form> </body> </html>\[/code\]
PHP output image
- Thread starter man75
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