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i have a jquery mobile issue, i want to display the returned data from php into a jquery mobile dialog.How do i go about it.here the code from Chad Lung. Please can someone help me modify this.File name: callajax.php\[code\] <?php $firstName = $_POST[firstName]; $lastName = $_POST[lastName]; echo("First Name: " . $firstName . " Last Name: " . $lastName);?>\[/code\]File name: index.html\[code\] <!DOCTYPE html><html> <head> <title>Submit a form via AJAX</title> <link rel="stylesheet" href="http://code.jquery.com/mobile/1.0a4/jquery.mobile-1.0a4.min.css" /> <script src="http://code.jquery.com/jquery-1.5.2.min.js"></script> <script src="http://code.jquery.com/mobile/1.0a4/jquery.mobile-1.0a4.min.js"></script></head><body> <script> function onSuccess(data, status) { data = http://stackoverflow.com/questions/8008178/$.trim(data); $("#notification").text(data); } function onError(data, status) { // handle an error } $(document).ready(function() { $("#submit").click(function(){ var formData = http://stackoverflow.com/questions/8008178/$("#callAjaxForm").serialize(); $.ajax({ type: "POST", url: "callajax.php", cache: false, data: formData, success: onSuccess, error: onError }); return false; }); }); </script> <!-- call ajax page --> <div data-role="page" id="callAjaxPage"> <div data-role="header"> <h1>Call Ajax</h1> </div> <div data-role="content"> <form id="callAjaxForm"> <div data-role="fieldcontain"> <label for="firstName">First Name</label> <input type="text" name="firstName" id="firstName" value="" /> <label for="lastName">Last Name</label> <input type="text" name="lastName" id="lastName" value="" /> <h3 id="notification"></h3> <button data-theme="b" id="submit" type="submit">Submit</button> </div> </form> </div> <div data-role="footer"> <h1>GiantFlyingSaucer</h1> </div> </div></body></html>\[/code\]