8TrackMind
New Member
Basically I want to run the Google Analytics on the server and not show the 1px .GIF (the reason for this is that I want to display an image without it being in HTML but as a Content-type: image/jpeg\[code\] $GA_ACCOUNT = "MO-3845491-5"; $GA_PIXEL = "ga.php"; function googleAnalyticsGetImageUrl() { global $GA_ACCOUNT, $GA_PIXEL; $url = ""; $url .= $GA_PIXEL . "?"; $url .= "utmac=" . $GA_ACCOUNT; $url .= "&utmn=" . rand(0, 0x7fffffff); $referer = $_SERVER["HTTP_REFERER"]; $query = $_SERVER["QUERY_STRING"]; $path = $_SERVER["REQUEST_URI"]; if (empty($referer)) { $referer = "-"; } $url .= "&utmr=" . urlencode($referer); if (!empty($path)) { $url .= "&utmp=" . urlencode($path); } $url .= "&guid=ON"; return $url; }$googleAnalyticsImageUrl = googleAnalyticsGetImageUrl(); //echo '<img src="' . $googleAnalyticsImageUrl . '" />'; //open the google script with all our settings to generate the 1px x 1px blank gif which reports to GA $handle = fopen ($googleAnalyticsImageUrl, "r"); $test = fgets($handle); echo $test; fclose($handle); //Pretend this page was a jpg image all along and get the jpg and return it.$imageurl = fopen ('http://www.default.com/test.jpg', "r"); //this is where the real file should be locatedwhile (!feof ($imageurl)) { $image = fgets($imageurl, 4096); header('Content-type: image/jpeg'); echo $image;}fclose($imageurl);\[/code\]Any help would be greatly appreciated as I am very new to GA