webmasterbeta
New Member
We would like to have a link from our xsl style sheet that takes you to anotherpage. The specific xml tag is assigned correctly with a value of classinfo.asp?idnumber=1.However, when we try to view our xsl page, nothing appears for the link.I think it is a syntax problem that we are missing. Can someone please helpus? Thanks.Below is our style sheet.<?xml version="1.0"?><xsl:stylesheet xmlns:xsl="http://www.w3.org/TR/WD-xsl"><xsl:template match="/"><classlist><xsl:apply-templates select="//class" order-by="name"/></classlist></xsl:template><xsl:template match="class"><class><name> <xsl:value-of select="name"/> </name><type> <xsl:value-of select="type"/> </type><date> <xsl:value-of select="date"/> </date><time> <xsl:value-of select="time"/></time><classinfo><xsl:apply-templates select="classinfo"/> </classinfo></class></xsl:template><xsl:template match="classinfo"><xsl:element name="A"><xsl:attribute name="HREF"><xsl:value-of /></xsl:attribute>classinfo</xsl:element></xsl:template></xsl:stylesheet