PhelvePully
New Member
I need to format XML input using XSL to obtain more convenient structure. As a next step of processing i want to transform it to HTML. Suppose i have the following input: (0)\[code\]<list><item item-id="1" second-item-id="1" third-item-id="1"/><item item-id="1" second-item-id="1" third-item-id="2"/><item item-id="1" second-item-id="2" third-item-id="1"/><item item-id="1" second-item-id="3" third-item-id="1"/><item item-id="2" second-item-id="1" third-item-id="1"/><item item-id="2" second-item-id="1" third-item-id="2"/><item item-id="2" second-item-id="1" third-item-id="3"/><item item-id="2" second-item-id="2" third-item-id="1"/><item item-id="3" second-item-id="1" third-item-id="1"/><item item-id="3" second-item-id="1" third-item-id="2"/><item item-id="3" second-item-id="1" third-item-id="3"/><item item-id="3" second-item-id="1" third-item-id="4"/></list>\[/code\]and the following XSL template: (1)\[code\]<?xml version="1.0" encoding="UTF-8"?><xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl
utput indent="yes"/> <xsl:key name="itemKey" match="item" use="@item-id"/> <xsl:key name="secondItemKey" match="item" use="concat(@item-id, '|', @second-item-id)"/> <xsl:template match="list"> <xsl:copy> <xsl:copy-of select="@*"/> <xsl:apply-templates select="item[generate-id() = generate-id(key('itemKey', @item-id)[1])]"/> </xsl:copy> </xsl:template> <xsl:template match="item"> <item item-id="{@item-id}"> <xsl:apply-templates select="key('itemKey', @item-id)[generate-id() = generate-id(key('secondItemKey', concat(@item-id, '|', @second-item-id))[1])]" mode="evt"/> </item> </xsl:template> <xsl:template match="item" mode="evt"> <second-item second-item-id="{@second-item-id}"> <xsl:apply-templates select="key('secondItemKey', concat(@item-id, '|', @second-item-id))" mode="bus"/> </second-item> </xsl:template> <xsl:template match="item" mode="bus"> <third-item third-item-id="{@third-item-id}"/> </xsl:template> </xsl:stylesheet>\[/code\]it gives me pretty fine XML: (2)\[code\]<?xml version="1.0"?><list> <item item-id="1"> <second-item second-item-id="1"> <third-item third-item-id="1"/> <third-item third-item-id="2"/> </second-item> <second-item second-item-id="2"> <third-item third-item-id="1"/> </second-item> <second-item second-item-id="3"> <third-item third-item-id="1"/> </second-item> </item> <item item-id="2"> <second-item second-item-id="1"> <third-item third-item-id="1"/> <third-item third-item-id="2"/> <third-item third-item-id="3"/> </second-item> <second-item second-item-id="2"> <third-item third-item-id="1"/> </second-item> </item> <item item-id="3"> <second-item second-item-id="1"> <third-item third-item-id="1"/> <third-item third-item-id="2"/> <third-item third-item-id="3"/> <third-item third-item-id="4"/> </second-item> </item></list>\[/code\]i have another XSL which transforms XML #2 to html:\[code\]<?xml version="1.0" encoding="UTF-8"?><xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xslutput indent="yes" method="html"/> <xsl:template match="list"> <xsl:for-each select="item"> <h2><xsl:value-of select="concat(local-name(),' ',@item-id)"/></h2> <ul> <xsl:for-each select="second-item"> <li><xsl:value-of select="concat(local-name(),' ',@second-item-id)"/></li> <ul> <xsl:for-each select="third-item"> <li><xsl:value-of select="concat(local-name(),' ',@third-item-id)"/></li> </xsl:for-each> </ul> </xsl:for-each> </ul> </xsl:for-each> </xsl:template></xsl:stylesheet>\[/code\]So here is the question: I want to process input xml with both of tempaltes (or merged one) in one step. How can i do it? Thanks in advance.
utput indent="yes"/> <xsl:key name="itemKey" match="item" use="@item-id"/> <xsl:key name="secondItemKey" match="item" use="concat(@item-id, '|', @second-item-id)"/> <xsl:template match="list"> <xsl:copy> <xsl:copy-of select="@*"/> <xsl:apply-templates select="item[generate-id() = generate-id(key('itemKey', @item-id)[1])]"/> </xsl:copy> </xsl:template> <xsl:template match="item"> <item item-id="{@item-id}"> <xsl:apply-templates select="key('itemKey', @item-id)[generate-id() = generate-id(key('secondItemKey', concat(@item-id, '|', @second-item-id))[1])]" mode="evt"/> </item> </xsl:template> <xsl:template match="item" mode="evt"> <second-item second-item-id="{@second-item-id}"> <xsl:apply-templates select="key('secondItemKey', concat(@item-id, '|', @second-item-id))" mode="bus"/> </second-item> </xsl:template> <xsl:template match="item" mode="bus"> <third-item third-item-id="{@third-item-id}"/> </xsl:template> </xsl:stylesheet>\[/code\]it gives me pretty fine XML: (2)\[code\]<?xml version="1.0"?><list> <item item-id="1"> <second-item second-item-id="1"> <third-item third-item-id="1"/> <third-item third-item-id="2"/> </second-item> <second-item second-item-id="2"> <third-item third-item-id="1"/> </second-item> <second-item second-item-id="3"> <third-item third-item-id="1"/> </second-item> </item> <item item-id="2"> <second-item second-item-id="1"> <third-item third-item-id="1"/> <third-item third-item-id="2"/> <third-item third-item-id="3"/> </second-item> <second-item second-item-id="2"> <third-item third-item-id="1"/> </second-item> </item> <item item-id="3"> <second-item second-item-id="1"> <third-item third-item-id="1"/> <third-item third-item-id="2"/> <third-item third-item-id="3"/> <third-item third-item-id="4"/> </second-item> </item></list>\[/code\]i have another XSL which transforms XML #2 to html:\[code\]<?xml version="1.0" encoding="UTF-8"?><xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xslutput indent="yes" method="html"/> <xsl:template match="list"> <xsl:for-each select="item"> <h2><xsl:value-of select="concat(local-name(),' ',@item-id)"/></h2> <ul> <xsl:for-each select="second-item"> <li><xsl:value-of select="concat(local-name(),' ',@second-item-id)"/></li> <ul> <xsl:for-each select="third-item"> <li><xsl:value-of select="concat(local-name(),' ',@third-item-id)"/></li> </xsl:for-each> </ul> </xsl:for-each> </ul> </xsl:for-each> </xsl:template></xsl:stylesheet>\[/code\]So here is the question: I want to process input xml with both of tempaltes (or merged one) in one step. How can i do it? Thanks in advance.