Problems with javascript/php image positioning system

Kerfur

New Member
I am working on a project which involves moving products around a virtual living room, I have the following function\[code\]<a href="javascript:void(0)" onclick="sendxandy( <? echo $_SESSION['numberOfProducts']; ?> )">Save Positions of Products</a>\[/code\]and then the function is as follows:`function sendxandy(productAmount){ if (productAmount == 1) { location.href="http://stackoverflow.com/questions/2114911/homeview.php?x=" + dd.elements.image1.x + "&y=" + dd.elements.image1.y; } if (productAmount == 2) { location.href="http://stackoverflow.com/questions/2114911/homeview.php?x=" + dd.elements.image1.x + "&y=" + dd.elements.image1.y + "&xtwo= " + dd.elements.image2.x + "&ytwo=" + dd.elements.image2.y; } if (productAmount == 3) { location.href="http://stackoverflow.com/questions/2114911/homeview.php?x=" + dd.elements.image1.x + "&y=" + dd.elements.image1.y + "&xtwo= " + dd.elements.image2.x + "&ytwo=" + dd.elements.image2.y + "&xthree= " + dd.elements.image3.x + "&ythree=" + dd.elements.image3.y; } if (productAmount == 4) { location.href="http://stackoverflow.com/questions/2114911/homeview.php?x=" + dd.elements.image1.x + "&y=" + dd.elements.image1.y + "&xtwo= " + dd.elements.image2.x + "&ytwo=" + dd.elements.image2.y + "&xthree= " + dd.elements.image3.x + "&ythree=" + dd.elements.image3.y + "&xfour= " + dd.elements.image4.x + "&yfour=" + dd.elements.image4.y; } if (productAmount == 5) { location.href="http://stackoverflow.com/questions/2114911/homeview.php?x=" + dd.elements.image1.x + "&y=" + dd.elements.image1.y + "&xtwo= " + dd.elements.image2.x + "&ytwo=" + dd.elements.image2.y + "&xthree= " + dd.elements.image3.x + "&ythree=" + dd.elements.image3.y + "&xfour= " + dd.elements.image4.x + "&yfour=" + dd.elements.image4.y + "&xfive= " + dd.elements.image5.x + "&yfive=" + dd.elements.image5.y;}`and the function continues just like this up to image 10. so as you can see the coordinates of the image are saved in the URL so that I can access them in php, my next function is this \[code\]<a class="code" href="javascript:void(0);" onclick="moveProduct(<? echo $_SESSION['numberOfProducts']; ?>)">Move Images Back</a>\[/code\]and inside here i have this (the moveTo variables are php variables for some reason this display can't print the code, also the moveTo is another function which is provided by a second script):`function moveProduct(moveAmount){ if (moveAmount == 1) { if(window.dd && dd.elements) { dd.elements.image1.moveTo(, ); } } if (moveAmount == 2) { if(window.dd && dd.elements) { dd.elements.image1.moveTo(, ); dd.elements.image2.moveTo(, ); } } if (moveAmount == 3) { if(window.dd && dd.elements) { dd.elements.image1.moveTo(, ); dd.elements.image2.moveTo(, ); dd.elements.image3.moveTo(, ); } }`now i know my loop structure is god awful :) but please bear with me. whats happens is inside the moveProduct function, whatever the last if "moveAmount == " is, then images will only be relocated at that number. for example if I have the function set as above only three images will be remembered, not one or two, or four or five, but three only. i actually have ten items so i have the above functions set up for 10 items, and ONLY 10 images will be remembered. When i run the function moveProduct when theres not 10 items on the page, nothing happens at all like I'll load one image, move it, click save, everything looks fine but when i move it back to remembered coordinates nothing happens.please help any advice would be appreciated
 
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