PHP exit(); function

liunx

Guest
Hi, I'm writing a php script at the moment and I came across a minor problem...
I have this script right between the template html codes. Within the script I use if-else statement for error checking and whenever there's an error I use the exit(); function so the script won't go any further. Bu the problem is that the html just under the script won't display...

I think it's the exit(); that's doing it... Can anyone help me out on this? is there an alternative way? any way to getting around this problem?

Thanks.php questions in the php forum :)if the exit function is in the if statement then nothing after it will continue. it doesn't just break out of the if statement it stops the whole script.
 
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