i got error while coding of pagination in php5?

[naireelve]

i am writing code of pagination & i got an error.this is my code :\[code\]<?php mysql_connect("localhost", "root", "") or die(mysql_error()); mysql_select_db("Admin") or die(mysql_error()); if (isset($_GET["page"])) { $page = $_GET["page"]; } else { $page=1; }$start_from = ($page-1) * 2; $sql = "SELECT * FROM events ORDER BY event ASC LIMIT $start_from, 2"; $result = mysql_query ($sql) or die(mysql_error()); $num=mysql_numrows($result);$x=0;?> <table><tr><td>Event</td><td>Types</td></tr><?php while ($x<$num) {$row1 = mysql_result($result,$x,'event');$row2 = mysql_result($result,$x,'types'); ?> <tr> <td><? echo $row1; ?></td> <td><? echo $row2; ?></td> </tr><?php $x++;} ?> </table><?php $sql = "SELECT COUNT(event) FROM events"; $result = mysql_query($sql) or die(mysql_error()); $row = mysql_fetch_row($result); $total_records = $row[0]; $total_pages = ceil($total_records / 2); for ($i=1; $i<=$total_pages; $i++) { echo "<a href='http://stackoverflow.com/questions/3802704/pagination.php?page=".$i."'>".$i."</a> "; }?>\[/code\]now i got an error. \[code\] object not found\[/code\]