Kxsmuwuhtwfnf
New Member
I have the following XML structur:\[code\] <example> <data> <numberGer>3,40</numberGer> </data> <data> <numberGer>7,40</numberGer> </data> <data> <numberGer>17,40</numberGer> </data> </example>\[/code\]I need the sum of all the "numberGer" nodes. The formating of the number is a problem. Because of the use of "," the function "sum" produces a error. So something like sum(//numberGer) does not work. I can use XSLT 2.0 functions.I think I need to write a recursive template, which takes the computed value and a list of nodes.Somethink like :\[code\]<xsl:template name="addGerNumbers"> <xsl
aram name="number"/> <xslaram name="nodes"/> <xsl:choose> <xsl:when test="$nodes"> <xsl:variable name="recursive_result"> ... <xsl:call-template name="addGerNumbers"> ... </xsl:call-template> </xsl:variable> <xsl:value-of select="$number + $recursive_result"/> </xsl:when> <xsl
therwise> <xsl:value-of select="0"/> </xsltherwise> </xsl:choose> </xsl:template>\[/code\]At the end I need a single value as an result.How to XPath sum() all previous nodes in a XSL for-each loop? Does not work for me, because I need a single number at the end.Any ideas?
aram name="number"/> <xslaram name="nodes"/> <xsl:choose> <xsl:when test="$nodes"> <xsl:variable name="recursive_result"> ... <xsl:call-template name="addGerNumbers"> ... </xsl:call-template> </xsl:variable> <xsl:value-of select="$number + $recursive_result"/> </xsl:when> <xsltherwise> <xsl:value-of select="0"/> </xsltherwise> </xsl:choose> </xsl:template>\[/code\]At the end I need a single value as an result.How to XPath sum() all previous nodes in a XSL for-each loop? Does not work for me, because I need a single number at the end.Any ideas?