2 xslt question

[admin]

1)if i have a <div></div> (div wit nohgiht in between)
how can i make it t ostay as it is in the transformation so i wont get <div/> ???
2)how can i maintain the next code so it will be in 1 line and wont break to lines as the number of loops :


pager">

<xsl:call-template name="for.loop">

<xsl:with-param name="i">1</xsl:with-param>

<xsl:with-param name="count"><xsl:value-of select="count(//GamesZone/GameType[@Ref='1']/Category[@id=$CatId]/Game)"/></xsl:with-param>

</xsl:call-template>

<!--li class="active">1</li-->

</ul>


and the template===>>>>


<xsl:template name="for.loop">

<xslaram name="i" />

<xslaram name="count" />

<!--begin_: Line_by_Line_Output -->

<xsl:if test="($i <= $count) and ($i mod 5=1)">

<li class="active"><xsl:value-of select="floor($i div 5)+1" /></li>

</xsl:if>



<!--begin_: RepeatTheLoopUntilFinished-->

<xsl:if test="$i <= $count">

<xsl:call-template name="for.loop">

<xsl:with-param name="i">

<xsl:value-of select="$i + 1"/>

</xsl:with-param>

<xsl:with-param name="count">

<xsl:value-of select="$count"/>

</xsl:with-param>

</xsl:call-template>

</xsl:if>



</xsl:template>



how can i get this :

<ul class="pager"><li class="active">1</li><li>2></li></ul>

and not


<ul class="pager">
<li class="active">1</li>
<li>2</li>
</ul>



thnaks in advance
peleg